Question

A particle is moving along a circle such that it completes one revolution in 40 second in 2 minutes 20 seconds the ratio displacement point distance is

Answer 1

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area of circle =2πr
Cover 2πr in = 40 sec
In 2 min 20 sec., there are total seconds=>
60+60+20=180
Total distance covered in 180 second,
40+40+40+40+20=

#Distance covered in 20 second = πr

Total distance = 2πr+2πr+2πr+πr = 7πr

Displacement = 2r

Ratio of |Displacement| /distance=>>
2r/7πr = >
after putting the value of π=22/7
2r×7/ 7×22×r = 1/11


|displacement| /distance = 1/11