Question

A particle is moving along a circular path of radius 5 centimetre with a uniform speed of 5 metre per second

Answer 1

Average acceleration = average velocity/time

Average velocity = displacement/time

Average velocity = 2r/t =2*10/t =20/t = 5

t = 4 s

Average acceleration = 5/4 = 1.25 m/s^


Centripetal accl. is equal to v^2/r

ac = 5^2/5 = 5m/s^2.

Tangential accl.(at) is equal to

Change in velocity/ time taken.

Change in velocity = 5-(-5) =10.

Time period =( 2*pi. R) /V = 2*pi sec.

Time taken in half revolution is pi.

at = 10/pi



Do rest of the calculation