A particle is moving along a circular path of radius 5m with uniform speed 5m/s. What will be average acceleration when the particles completes half revolution
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Answered by
3
speed = 2 xpi x r / t
Time = 6.25 sec
velocity = 10 / 3.12
velocity = 3.2 m/s
accelration = 3.2 -0 / 3.12
acelration= 1.9 m/s^2
Time = 6.25 sec
velocity = 10 / 3.12
velocity = 3.2 m/s
accelration = 3.2 -0 / 3.12
acelration= 1.9 m/s^2
Answered by
9
Let the line AB represents a diameter of circle.
Velocity at
Point A = 5j
Point B = -5j
Time taken to take half revolution = d/v = πr / v = π *5/5 = π seconds
Average Acceleration = Change in velocity / Time
= (5j - (-5j)) / π
= 10j / π
Magnitude of average acceleration = 10/π m/s^2
Velocity at
Point A = 5j
Point B = -5j
Time taken to take half revolution = d/v = πr / v = π *5/5 = π seconds
Average Acceleration = Change in velocity / Time
= (5j - (-5j)) / π
= 10j / π
Magnitude of average acceleration = 10/π m/s^2
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