Question

a particle is moving along a circular path of radius r with uniform speed v through what angle does its angular velocity change when it completes half of circular path?
Ans is 0 degrees but how?

Answer 1

The formula of the dot product of two vectors, say P⃗ P→ and Q⃗ Q→ is given by:

P⃗ .Q⃗ =|P| |Q| cosθP→.Q→=|P| |Q| cosθ

Here, we may conclude that when angle between two vectors i.e. θθ is equal to zero, it means that the vectors are parallel....
The collinear vectors are the vectors that are either parallel to each other or are in the same line. ....In any case, such vectors should not be inclined by some angle, i.e. the angle ....between collinear vectors must be zero.

Since cos 0 = 1

Therefore, we can say that the dot product of two collinear vectors is equal to the product of magnitudes of the vectors.

Answer 2

Answer:

0°

Explanation:

Since angular velocity is v/(2 pi r)) It does not change with the position of the particle on the circle as it only depends on v and r