Question

A particle is moving along a circular track of radius 1 m with uniform speed what is the ratio of the distance covered and the displacement in half revolution

Answer 1

Hola mate.....here is your answer.....

$\: here \: you \: have \: given \: that \: \\ the \: radius \: of \: the \: circular \\ \: tract \: along \: which \: particle \\ \: is \: moving \: is \: 1 \: m. \\ \\ the \: distance \: and \: displacement \\ \: of \: the \: particle \: after \: half \: \\ of \: circumference \: \: are \: = \\ \\ distance \: = \: \pi \: r \: = \: \pi \: \times 1 \: = \: \pi \: metre \: \\ displacement \: \: = r + r = 2r \: = 2 \times 1 = 2 \: metre \\ \\ hence \: \: \: \frac{distance}{displacement} \: = \: \frac{\pi}{2} \\ \\ so \: your \: answer \: is \: \\ \\ \: \: \: \: \: distance : displacement = \: \pi : 2$


hope u understood ^_^