Physics, asked by sujalagrawal676, 16 days ago

A particle is moving along a curved path as shown. The distance AB (Path length) is the same as the distance BC (path length). The distance AB is covered at a speed V, and BC at a speed V₂. Calculate the average speed for the entire journey.​

Answers

Answered by crankybirds30
0

Answer:

refer the attachment

Explanation:

A particle is moving along a curved path as shown. The distance AB (Path length) is the same as the distance BC (path length). The distance AB is covered at a speed V, and BC at a speed V₂. Calculate the average speed for the entire journey.

Attachments:
Answered by amikkr
0

Given: Distance AB is equal to distance BC

         The speed at which path AB is covered = v₁

          The speed at which path BC is covered = v₂

To find: Average speed for the entire journey

Solution: Average speed of a body is equal to the total distance covered by the body divided by the total elapsed time.

  • Speed is the distance covered by the body per unit of time.
  • Total elapsed time is the ratio of total distance by the speed of the body in moving that particular distance.
  • Distance is the measurement of the path which the body follows.

Total distance covered by the body = AB + BC

Elapsed time to cover the distance of path AB is t₁ = AB/v₁

Elapsed time to cover the distance of path BC is t₂ = AB/v₂

Total elapsed time = t₁ + t₂

                               = AB/v₁ + BC/v₂

Therefore, the average speed is given by = total distance covered / total elapsed time =  \frac{AB + BC}{AB/v1 + BC/v2 }

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