Question

A particle is moving along a straight line path given by Y= ct^6/6 (where c is a positive constant.) The relation Between the acceleration (A) and Velocity(v) Of the particle at t=5sec is​

Answer 1

Answer:

acceleration = Velcoity at t = 5 sec

Explanation:

A particle is moving along a straight line path given by Y= ct^6/6 (where c is a positive constant.) The relation Between the acceleration (A) and Velocity(v) Of the particle at t=5sec is​

Y  = ct⁶/6

Velocity = dY/dt  = 6ct⁵/6 = ct⁵

Acceleration = dV/dt  = 5ct⁴

Velocity at 5 sec = c5⁵

acceleration at 5 sec = 5c5⁴ =c5⁵

acceleration = Velcoity at t = 5 sec

Answer 2

Explanation:

just wanted to inform here the correct answer