Question

A particle is moving along a straight line SN is equals to 2 + 0. n find the initial velocity and acceleration​

Answer 1

Answer:

Following :-my dear friend

Explanation:

We know distance traveled in n

th

second is given as S

n

=u+f(2n−1)/2.

So comparing with given expression we get ,u+fn−f/2=2+0.4n ......1

Now comparing the coefficients of n , we get f=0.4units

and now put f=0.4 in equation-1 we get u=2.2units