A particle is moving along a straight line with constant acceleration 8ms^-2. Find the change in velocity during the time interval t = 1sec to t = 3sec. Also calculate the displacement during this time interval. (To use indefinite integration; initial displacement = 6m, initial velocity = -2ms^-1)
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u=5m/s
v=15m/s
t=5s
v=u+at
15=5+a×5
a=2m/s
2
v
2
=u
2
+2as
225=25+2×2×s
s=
4
200
=50m
s
5th
=u+
2
a
(2×8−1)
=5+1(15)=20
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