Question

A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes 20m/s and in tenth second it travels a distance of 10m. Then find the acceleration of the particle.

Answer 1

Given

t= 10 s , v= 20 m/s , u=0 ,. s= 10 m

Solution

s=ut + 1/2 at^2

s= 0×10 + 1/2 a ×10^2

10= 0 + 1/2 a × 100

10= 1/2 a × 100

10= 50 a

a = 10/50 = 1/5

a= 0.2 m/s^2

Answer 2

Answer:

Below is the solution for this question

Explanation:

v=u+at

20=u+a*10.............( 1)

S(nth)=u+a/2(2n-1)

10=u+a/2(2*10-1).............(2)

On solving equation 1 and 2 we get

a=20 m/s^2