Question

A particle is moving along a straight line y =
3 m at a velocity 5 m/s. Its angular speed
about origin when it is at point P(4 m, 3 m)
is​

Answer 1

Answer:

w = v sin(Q) / r

Where r is the position vector of point P(4m, 3m)

v sin(Q) is the perpendicular component of velocity to the position vector.

OP = r = √(16m2 + 9m2 ) = 5m

sin(Q) = 3/5

-

w = (5 x 3/5) / 5 = 0.6 radian / second