Question

a particle is moving along circular path of radius 1m calculate the distance and displacement travelled during half revolution and one quarter of the path​

Answer 1

Explanation:

Displacement is the shortest distance travelled from the initial point to the final point. After half revolution the displacement is the length of the diameter which is equal to 2r. Hence the displacement is 2r.

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Answer 2

Answer:

10/π ms^-2

Explanation:

when the particle completes half revolution change in velocity

∆v = (5-(-5))m/s = 10m/s

Time taken to complete the half revolution is

t = πr/v = (πr ×5)/5 = πs

Thus, average acceleration = ∆v/t = 10/π m/s^2