a particle is moving along circular path of radius 5 m and with uniform speed 5 m/s What will be the average acceleration when particle complete half revolution
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Let we assume particle starts from A. And ends at B. Hence, the initial and final points are opposite to each other.
Hence, as Initial velocity is 5 m/s,
Final velocity will be -5 m/s
Because they are opposite to each other.
Particle is moving along circular path so distance will be :
π × r
π × 5 = 5 π m.
We know,
Speed = Distance / Time (time is not given)
Time = Distance / Speed
= 5 π / 5
= π s.
Average acceleration = (Final velocity) −(Initial velocity) / Time Taken
= 5−(−5)/π m/s²
= 5 + 5 / π m/s²
= 10 / π m/s²
Average acceleration of particle is 10 / π m/s².
Thanks for your question !
Hence, as Initial velocity is 5 m/s,
Final velocity will be -5 m/s
Because they are opposite to each other.
Particle is moving along circular path so distance will be :
π × r
π × 5 = 5 π m.
We know,
Speed = Distance / Time (time is not given)
Time = Distance / Speed
= 5 π / 5
= π s.
Average acceleration = (Final velocity) −(Initial velocity) / Time Taken
= 5−(−5)/π m/s²
= 5 + 5 / π m/s²
= 10 / π m/s²
Average acceleration of particle is 10 / π m/s².
Thanks for your question !
Pratik3181:
thanks
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