a particle is moving along east direction with a velocity v metre per second and suddenly turns along north direction with the same velocity v then it resultant velocity is
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Initial velocity =v1=5m/s seast wards.
then after time t=10 sec
towards east =5m/s
v2=5m/s north wards.
towards east =5m/s
V resultant =v12+v22
=25+25=52
acceleration a=v=velocity/time
=1052=22×22=21towardsn−w
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