Question

a particle is moving along east direction with a velocity v metre per second and suddenly turns along north direction with the same velocity v then it resultant velocity is​

Answer 1

Initial velocity =v1=5m/s seast wards.

then after time t=10 sec

towards east =5m/s

v2=5m/s north wards.

towards east =5m/s

V resultant =v12+v22

=25+25=52

acceleration a=v=velocity/time

=1052=22×22=21towardsn−w