Question

a particle is moving along its particle is moving along its straight line with different velocities 20 kmph in 5sec, 40kmph in 10 sec, 60 kmph in 15 sec. Then the distance covered is more in​

Answer 1

Given:

A particle is moving along a straight line with different velocities 20 kmph in 5sec, 40kmph in 10 sec, 60 kmph in 15 sec.

To find:

Distance covered is maximum in which case.

Calculation:

In the 1st case:

$distance = velocity \times time$

$= > d1 = 20 \times \dfrac{5}{60 \times 60}$

$= > d1 = 20 \times \dfrac{5}{3600}$

$= > d1 = 0.027 \: km$

In the 2nd case:

$distance = velocity \times time$

$= > d2 = 40 \times \dfrac{10}{60 \times 60}$

$= > d2 = 40 \times \dfrac{10}{3600}$

$= > d2 = 0.111 \: km$

In the 3rd case:

$distance = velocity \times time$

$= > d3 = 60 \times \dfrac{15}{60 \times 60}$

$= > d3 = \cancel{60} \times \dfrac{15}{60 \times \cancel{60}}$

$= > d3 = 0.25 \: km$

Hence, final answer is:

$\boxed{ \red{ \large{ \bold{d3 > d2 > d1}}}}$

Maximum Distance covered in 3rd case.