a particle is moving along line y = 4x with a speed 10m/s. if the mass of the particle is 2 kg then it's angular momentum about the point (1,4) is
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Answer:
L=mvr where r=perpendicular distance of velocity from origin.
Since velocity is along line 3x+4y−5=0
Hence,distance from origin(0,0) is r=
3
2
+4
2
∣3×0+4×0−5∣
=1
Hence,L=2×8×1
⟹L=16kgm/s
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