Physics, asked by shreejaabuddy5620, 7 months ago

A particle is moving along positive x-axis . its position varies as x= t^3-3t^2+12t+20. what is the velocity of the particle when its acceleration is zero

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Answered by waizayas1234
0

Answer:

by x = ( - 2t3 + 3t2 + 5)m . The acceleration of particle at the instant its velocity becomes zero is. ... The position of a particle moving along x- axis is given by. x=(−2t3+3t2+5)m. Velocity ...

Top answer:

The position of a particle moving along x - axis is given by x = ( - 2t3 + 3t2 + 5)m Velocity, v = dxdt = 0 - 6t2 + 6t = 0 . . . . . . .(1) 6t( - t + 1) ...

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