A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t) = (t)in(2t). Find the acceleration of the particle when the velocity is first zero
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Please find below the solution to the asked query:
x=3t2−5y=2tVelocity vector is given by:v⃗ =vxiˆ+vyjˆvx=dxdt=ddt(3t2−5)=6t−0=6tvy=dydt=ddt(2t)=2Hencev⃗ =6tiˆ+2jˆ ...Option(A)
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Please find below the solution to the asked query:
x=3t2−5y=2tVelocity vector is given by:v⃗ =vxiˆ+vyjˆvx=dxdt=ddt(3t2−5)=6t−0=6tvy=dydt=ddt(2t)=2Hencev⃗ =6tiˆ+2jˆ ...Option(A)
Hope this information will clear your doubts about this topic.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Regards
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