Question

a particle is moving along the x axis with an acceleration a=2x where a is in ms^-2and x is in meter . if the partical starting from rest at x=1m find its velocity when it reaches the position​

Answer 1

Answer:

Hope this helps.

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Thank you.

Answer 2

Answer:

v=x

2

+x

⇒

dx

dv

=2x+1

∴a=

dx

vdv

=(x

2

+x)(2x+1)

∴atr=2

a=(4+2)(4+1)

=30m/s

2

∴ Option D is correct answer.