Question

A particle is moving along X-axis. At time t1 = 3s, its position is x1 = 6m and at t2 = 8s, its position is x2 = 21m. What is its average velocity?​

Answer 1

Answer:Hi here's answer...

t1= 3 sec

d1= 6 m

then, S1 = d1/t1 = 6/3= 3

t2= 8

d2= 21

then, S2= d2/t2= 21/8

A. V. = total distance/ total time

then, step by step

explanation

Explanation:

Answer 2

Answer:

3ms-1

Explanation:

21m-6m=15m

8s-3s=5s

=15m/5s

=3m/s

hope it helped you :)