Question

a particle is moving along x axis its initial velocity is 40m/s along positivr x axis and an acceleration of 10m/s2 along negative x axis particle starts from x=10 at what time the velocity of particle is zero
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Answer 1

Answer:

$\large{\red{\underline{\tt{Answer}}}}$

V= u+at

0=40 -10* or t=4 sec

for point where v=0,use

v^2-u^2=2 as

0-40^2=2*(-10)*s

s=1600/20

=80 m

Answer 2

Answer:

V= u+at

0=40 -10* or t=4 sec

for point where v=0,use

v^2-u^2=2 as

0-40^2=2*(-10)*s

s=1600/20

=80 m

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