A particle is moving along x axis.
Its initial velocity is 40m/sec along positive x axis.
It has an acceleration of 10m/s square along negative x axis.
If particle starts from x=10m then find the velocity of particle at origin.
Answers
0=40 -10* or t=4 sec
for point where v=0,use
v^2-u^2=2 as
0-40^2=2*(-10)*s
s=1600/20
=80 m
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The particle has travelled 80 metres before coming to a complete stop.
What is Newton's law in simple terms?
- A statement in dynamics: a body at rest remains at rest and a body in motion remains in uniform motion in a straight line unless acted upon by an external force called also Newton's first law of motion.
What are Newton's three laws?
- In the first law, we understand that an object will not change its motion unless a force acts on it.
- The second law states that the force on an object is equal to its mass times its acceleration.
- And finally, the third law states that there is an equal and opposite reaction for every action.
According to the question:
Newton's 1st equation of motion :
v = u + at
Newton's 2nd equation of motion :
s = ut + ½at²
Newton's 3rd equation of mother :
v² = u² + 2as
Given :
• Initial position on x-axis ; x = 10 m
• Initial velocity ; u = 40 m/s
• Acceleration ; a = 10 m/s²
• Final velocity ; v = 0 m/s
The particle is moving in postive x-axis and has negative acceleration which means the velocity of particle is slowing down and gradually the particle will come at rest .
Thus ,Final velocity , v = 0 m/s
Now ,Using the Newton's 3rd equation of motion , we have ;
= v² = u² + 2as
= 0² = 40² + 2×(-10)s
= 0 = 160 - 20s
20s = 160
s = 160/20
s = 80
Hence ,The distance travelled by the particle till it comes at rest is 80m .
Learn more about Newton's law here,
https://brainly.in/question/875699?msp_poc_exp=5
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