Question

a particle is moving along x axis such that is position coordinates are ,(2,0) at t=0 , (6,0) m at t=2 , (13,0) m at t = 5 ; the magnitude of average velocity of particle from t = 0 to t=5 sec is

Answer 1

Total displacement = Final - Initial position = 13 - 2 = 11 unit
Avg. velocity = total displacement / total time 
                     = 11 / 5
                     = 2.2 unit / sec 

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