Physics, asked by muraligm03, 9 months ago

A particle is moving along x-axis such that is velocity varies with time according to v = t – t2. Its average acceleration between t = 0 and t = 1 s is

Answers

Answered by Anonymous
1

a = ∆v/∆t

= v(0) - v(1)/∆t

= (0 - 0 - 1 + 1)/1 - 0

= 0 m/s^2

Answered by arnavyadav342
0

Answer:2/3

Explanation:

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