Question

A particle is moving along x-axis . The position of the particle at any instant is given by x = 5 +6t², where x is in meters, t is in second. The velocity of the particle at t = 2s is 
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Answer 1

Answer:

The displacement is given as: y=ut+21at2

where, u is the initial velocity and a is the acceleration

Comparing with given expression: 

y=−5t+6t2+2

u=−5m/s, a=12m/s2

So initial velocity is −5 m