Question

A particle is moving along x axis the relation between acceleration and position is given by a=-9x^2 if the velocity of particle is 0 at x =3 the v of particle at origin is

Answer 1

Given: v^2=108–9x^2. Differentiating the equation w.r to X , 2vdv/DX =0–18x ... from origin if the acceleration of a particle is given by a=x where x ... 2 v dv/dt ...