Question

a particle is moving at 3.14m/sec completes 10 rounds in a circular path of radius 18 m the time taken by it

Answer 1

Answer:

360 seconds

Explanation:

Given :

• Radius of the circular path = 18 metres

• No. Of rounds completed by it = 10 rounds

• Speed of the particle = 3.14 m/s

To find :

• Time taken by the particle

Circumference of the circular path = 2×3.14×r

Circumference of the circular path = 6.28×18

Circumference of the circular path = 113.04 metres

Distance = 10×113.04 = 1130.4

Time taken = distance /speed

Time taken = 1130.4/3.14

Time taken = 360 seconds

The time taken is equal to 360 seconds

Answer 2

${ \bold{ \huge{ \underline{ \rm{ \red{Question:-}}}}}}$



▪ A particle is moving at 3.14 m/sec completes 10 rounds in a circular path of radius 18m. The time taken by it is ??



${ \bold{ \huge{ \rm{ \underline{ \red{Solution:-}}}}}}$



${ \dagger{ \green{ \bold{ \: \: \: GIVEN- }}}}$



✭ Speed of the particle = 3.14 m/sec



✭ Number of revolution = 10 rounds



✭ Radius of the circular path( r ) = 18 m



${ \dagger{ \bold{ \green{ \: \: \: TO \: FIND }}}}$



➡ Time taken by the particle????



${ \rm{ \underline{ \blue{circumference \: of \: the \: circular \: path}}}}$



${ \boxed{ \rm{ \pink{circumference = 2 \: \pi \: r}}}}$



${ \sf{circumference = 2 \times 3.14 \times 18m}}$



▪ Total distance covered by the particle = circumference of the circular path × no. of revolutions



${ \sf{ \blue{distance = 2 \times 3.14 \times 18 \times 10 \: m}}}$



${ \sf{ \blue{speed = 3.14 \: m \: {sec}^{ - 1}}}}$



${ \star{ \rm{ \underline{ \pink{ \: \: time \: taken \: by \: the \: particle}}}}}$



${ \boxed { \boxed{ \rm{ \red{ \: \: time = \frac{distance}{speed} \: \: }}}}}$



${ \implies{ \sf{ \: time = \frac{2 \times 3.14 \times 18 \times 10 \: m}{3.14 \: m \: {sec}^{ - 1}}}} }$



${ \implies{ \sf{ \: \: time = 2 \times 18 \times 10 \: sec}}}$



${ \underline{ \boxed{ \bold{ \red{time = 360 \: sec}}}}}$



➡ Time = 360/60 min = 60 min



➡ Time = 60/60 hr = 1hr