A particle is moving eastwards with a velocity 10 m/s. In 5 seconds the velocity changes to 10 m/s south wards. Then average acceleration during this time is
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Initial velocity, u = 5 m/s due east
Final velocity, v = 5 m/s due north
Change in velocity, Δv = v – u = 5 m/s due north - 5 m/s due east
Δv = 5 m/s due north + 5 m/s due west [negative of east direction is west]
Δv = (v^2 + u^2)^1/2
Δv = 5√2 m/s
Direction of Δv is given by,
tanθ = v/u = -1
θ = -45°
Thus, the acceleration is a = Δv/t = 5√2/10 = 1/√2 m/s^2 and is directed towards North-West direction.
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Initial velocity, u = 5 m/s due east
Final velocity, v = 5 m/s due north
Change in velocity, Δv = v – u = 5 m/s due north - 5 m/s due east
Δv = 5 m/s due north + 5 m/s due west [negative of east direction is west]
Δv = (v^2 + u^2)^1/2
Δv = 5√2 m/s
Direction of Δv is given by,
tanθ = v/u = -1
θ = -45°
Thus, the acceleration is a = Δv/t = 5√2/10 = 1/√2 m/s^2 and is directed towards North-West direction.
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