Question

A particle is moving eastwards with a velocity of 5 ms-1. In 10 second the velocity changes to 5 ms- northwards The average accelera-tion in this time is

Answer 1

Answer:

Correct option is

A

2

1

ms

−2

N-W

v

A

=5

i

^

v

B

=5

j

^

Change in velocity =5

j

^

−5

i

^

Avg.acc

n

=

time

change in velocity

=

10

5

j

^

−5

i

^

=

2

j

^

−

i

^

Magnitude of this vector =

4

1

2

+1

2

=

2

1

Direction of this vector is tanθ=

1

−1

⟹θ=135

o

, i.e, N-W direction

Explanation:

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