A particle is moving eastwards with a velocity of 5m/s. In 10 sec the velocity to 5m/s northward. The average acceleration in this time is -----
1) 1/√2 m/s² towards north east
2) 1/2 m/s² north
3) zero
4) 1/√2 m/s² towards north west
explane in detail
Answers
Answered by
6
Vi =5i
Vf=5j
Avg acceleration =|(Vf -Vi)|/10
=|5j-5i)|10
=1/√2 m/s2
so the option 1 is the correct answer
Vf=5j
Avg acceleration =|(Vf -Vi)|/10
=|5j-5i)|10
=1/√2 m/s2
so the option 1 is the correct answer
ritikm3011:
and how did you find direction??????
Answered by
4
Hey friend ur answer...
Average acceleration = final velocity - initial velocity / time taken
a=fv-iv/t
so,
a= 5-5/10
= 0/10
=0
Therefore, the answer is zero .
Average acceleration = final velocity - initial velocity / time taken
a=fv-iv/t
so,
a= 5-5/10
= 0/10
=0
Therefore, the answer is zero .
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