Question

A particle is moving from rest with a constant acceleration 4m/s^2 for some time and then retards with 2m/s^2 for some time and then finally comes to rest. The total time during the motion is 12 seconds. The maximum velocity of the particle is?

SPAMMERS STAY AWAY...

Answer 1

V= u + at

V= 0 + 4 t

V= 4 t

now it retards with 2

V= u + at

0= 4t - 2 t1

4 t= 2 t1

2t = t1

t + t1 = 12

3t = 12

t= 4

So at 4 second velocity =.4t = 16

which is maximum