Question

A particle is moving in a circle has initial angular
velocity 50 rpm and has an angular acceleration of π
rad/s^2. Its angular velocity after one minute is
(1)110 rpm
(2) 850 rpm
(3)1850 rpm
(4) None of these​

Answer 1

Answer:

so great is the explanation

Answer 2

Option (3) 1850rpm is the answer

Given,

The initial angular velocity w₀ = 50rpm.

Angular acceleration $\alpha$ = $\pi$ rad / $s^{2}$.

Time t = 1minute or 60sec.

To Find,

The angular velocity after one minute.

Solution,

Given that,

The moving particle has an initial angular velocity of 50rpm.

i.e. w₀ = $\frac{50}{60}$×$2\pi$

w₀ = $\frac{5}{3}\pi$ .

Therefore, the angular velocity after 60second will be,

time t = 60s.

w = w₀+$\alpha t$

w = $\frac{5}{3}\pi$ + $\pi$×60

w = $\frac{5}{3}\pi + 60\pi$

w = $\frac{185}{3} \pi$ rad /sec.

We need to convert it into per minute.

$\frac{185}{3} \pi * \frac{60}{2\pi }$ = 1850rpm.

Hence, 1850rpm is the angular velocity of the moving particle after one minute.

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