Physics, asked by ParthNau, 20 days ago

A particle is moving in a circle of diameter 10m . Calculate the distance travelled by the particle and it's displacement on completing one and half revolution

Answers

Answered by harshalipawar765
14

Answer:

Here's the answer below!!!✌️

Explanation:

The distance covered by it on completing 2 revolutions is.

Distance =2×2πr

=2πD

=2π10

=20πm.

Hope so, this answer will help you!!!

Answered by MysticalStar07
2

D = 10m

 \bf \red{ r =  \dfrac{d}{2}}   \\ \bf  \purple{=  \dfrac{10}{2} } \\ \bf  \green{= 5m}

So,

Distance in 2 revolution is 2×2πr

 \bf  \blue{=2×2×3.14×5}  \\ </h3><h3> \bf  \green {=20×3.14} \\ </h3><h3> \bf \orange { =60.14}  \\ </h3><h3> \bf \pink { =60m}

Because the moves from one point and then comes back to that point Displacement in two rounds is 0

So,

Distance travelled = 60m

Displacement = 0m.

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