A particle is moving in a circle of diameter 14m.Calculae the distance covered
and the displacement when it completes 3 revolution
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Answer:
The LCM of 2,3,4 2 , 3 , 4 is the result of multiplying all prime factors the greatest number of times they occur in either number. The LCM of 2,3,4 2 , 3 , 4 is 2⋅2⋅3=12 2 ⋅ 2 ⋅ 3 = 12 .
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Answer:
displacement will be zero
distance =3×circumference of the circle
circumference =2×3.14×r
here,
R=D/2
R=14÷2
R=7m
circumference =3×3.14×7
=65.94m
distance covered=3×65.94
=197.8 m
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