Question

A particle is moving in a circle of diameter 20m .what is its distance and displacement if it has completed 2 rounds

Answer 1

Solution :

⏭ Given:

✏ Diameter of circle = 20m

✏ No.of rounds completed by particle = 2

⏭ To Find:

✏ Distance and displacement after 2 rounds.

⏭ Concept:

✏ Distance is defined as total length of path covered by moving particle.

✏ Displacement is defined as the shortest distance between the intial and final point.

⏭ Conversation:

✏ Radius of circular path = 20/2 = 10m

⏭ Calculation:

• Distance

$\implies \sf \: \red{distance = 2 \times 2\pi{r}} \\ \\ \implies \sf \: distance = 4 \times 3.14 \times 10 \\ \\ \implies \: \boxed{ \bold{ \sf{ \blue{distance = 125.6 \: m}}}} \: \bigstar$

• Displacement

$\implies \sf \: \green{\triangle{position} = 0} \\ \\ \implies \: \boxed{ \bold{ \sf{ \orange{displacement = 0 \: m}}}} \: \bigstar$

⏭ Additional information:

• Distance is scalar quantity.
• Distance has always positive magnitude.
• Displacement is vector quantity.
• Displacement can be positive, negative and zero.

Answer 2

$\large \underline{ \blue{ \boxed{ \bf \green{Required \: Answer}}}}$

In attached file.