A particle is moving in a circle of diameter 5 m find out the the diatance and displacement after 2 revolutions
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For the circular path,
diameter, d = 5 m
Number of revolutions = 2
So, DIstance covered = 2 * Circumference
= 2 * πd
= 2 * 22/7 * 5
= 220/7
≈ 31.43 m
Moreover, the particle comes back to its starting point after 2 revolutions. So, the displacement is 0 m.
diameter, d = 5 m
Number of revolutions = 2
So, DIstance covered = 2 * Circumference
= 2 * πd
= 2 * 22/7 * 5
= 220/7
≈ 31.43 m
Moreover, the particle comes back to its starting point after 2 revolutions. So, the displacement is 0 m.
Answered by
1
Radius is 2.5 m
Distance if 2 * Circumference of Circle=2(2*pi*r)=2 x 2 x 3.14 x 2.5=31.4m
Net Linear displacement is Zero Because Particle Returns to its mean Position
Distance if 2 * Circumference of Circle=2(2*pi*r)=2 x 2 x 3.14 x 2.5=31.4m
Net Linear displacement is Zero Because Particle Returns to its mean Position
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