a particle is moving in a circle of diameter 5m . calculate the distance covered and displacement when it completes 3 revolutions
Answers
Answered by
24
Hey ,
★Circumference = 2πr
2 . 22\7 . 5\2
220\14
★now , distance = 3× 220\14
660\14 = 330\7 = 47.1 m
.
★and displacement = 0 m (as final point = initial point)
★I.E.after 3 rounds the particle will be at the place where it started .
Wish it works
★Circumference = 2πr
2 . 22\7 . 5\2
220\14
★now , distance = 3× 220\14
660\14 = 330\7 = 47.1 m
.
★and displacement = 0 m (as final point = initial point)
★I.E.after 3 rounds the particle will be at the place where it started .
Wish it works
suresh123:
how displacement will be 0
Answered by
37
Given -
No. of revolution = n = 3
diameter = 5m
so radius = r = 5/2m
Now
Distance covered = No. revolution * circumference of circle
= n * 2πr
= 3 * 2π(5/2)
= 3 * π(5)
= 15 π
= 15 * 3.14 {Since π= 3.14}
= 47 .1 m
Now
Displacement = 0
{Since displacement is the final position - initial position }
-----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
No. of revolution = n = 3
diameter = 5m
so radius = r = 5/2m
Now
Distance covered = No. revolution * circumference of circle
= n * 2πr
= 3 * 2π(5/2)
= 3 * π(5)
= 15 π
= 15 * 3.14 {Since π= 3.14}
= 47 .1 m
Now
Displacement = 0
{Since displacement is the final position - initial position }
-----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
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