Question

A particle is moving in a circle of radius R = 3 m
with an angular speed 2 radian per second in
clockwise direction as given in the diagram. The
acceleration (in m/s2) of particle at point Pis
(1) -6î-63;
(3) -61 +63 9
12) -639-6)
(4) 61-63 )​

Answer 1

Explanation:

now solve for sin and cos compoments and add vectors

formula used for constipatel acc is w^2r

Answer 2

Answer:

As the angular speed of the particle is 2 rad/s hence we can say ω=2rad/s.

For the particle 2 types of acceleration is responsible which are centripetal(ac) and tangential(at).

Of which the tangential acceleration at any point will be 0 as there is no component of time in the given angular speed.

Thus, only centrepetal acceleration ac will work which is, ac=ω*2r=3*2*2 = 12m/s.

According to the figure there will be 2 components one cos and other sin which will be (ac)cos60(-i) + (ac)sin60(-j).

Thus the position of the particle will be P = -6i - 6√3j.