Question

A particle is moving in a circle of radius R = 3 m with an angular speed 2 radian per second in clockwis direction as given in the diagram. The acceleration (in m/s2) of particle at point P is​

Answer 1

Answer:

see attachment hope it helps you

Answer 2

Answer:$a_{c} = a_{c} cos60(-i)+a_{c} sin60(-j)\\a_{c} =-rw^{2} (\frac{1}{2} )(i)-rw^{2} (\frac{\sqrt{3} }{2} )(j)\\a_{c} =-3*2^{2} (\frac{1}{2} )(i)-3*(2^{2} )\frac{\sqrt{3} }{2} (j)\\a_{c} =-6i-6\sqrt{3} j ms^{-2}$

Explanation: