A particle is moving in a circular path of diameter 10 meter . Find disrance and displacement of the body on completing 2 revolutions.
Answers
Answered by
5
Hi there !
Answer down here ⬇️⬇️
Given,
Diameter of the circular path = 10m
Distance in one revolution = circumference of the circular path
=πd
= 3.14 × 10
= 31.4 m
Distance covered in 2 revolution = 31.4×2m = 62.8 m
Thus,
The distance covered in 2 revolution is 62.8 m
The DISPLACEMENT :
Since the body is moving in a circular path , the initial and the final points will lie on the same point ie, they'll coincide with each other. So,
The DISPLACEMENT will be 0
_______________
Hope it helps :D
Answer down here ⬇️⬇️
Given,
Diameter of the circular path = 10m
Distance in one revolution = circumference of the circular path
=πd
= 3.14 × 10
= 31.4 m
Distance covered in 2 revolution = 31.4×2m = 62.8 m
Thus,
The distance covered in 2 revolution is 62.8 m
The DISPLACEMENT :
Since the body is moving in a circular path , the initial and the final points will lie on the same point ie, they'll coincide with each other. So,
The DISPLACEMENT will be 0
_______________
Hope it helps :D
JinKazama1:
Well done bro :)
Answered by
2
Hey!
______________
Diameter of circular path = 10 m
Radius = 10/2 = 5 m
Circumference of circular path = 2πr
= 2 × 22/7 × 5
= 31.4 m
Distance travelled = 31.4 × 2 = 62.8 m
Displacement = Shortest distance travelled
Displacement = 0
As starting point and ending point is same.
_________________
Hope it helps...!!!
______________
Diameter of circular path = 10 m
Radius = 10/2 = 5 m
Circumference of circular path = 2πr
= 2 × 22/7 × 5
= 31.4 m
Distance travelled = 31.4 × 2 = 62.8 m
Displacement = Shortest distance travelled
Displacement = 0
As starting point and ending point is same.
_________________
Hope it helps...!!!
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