Question

A particle is moving in a circular path of radius 7 m with constant speed. it complets one revolution in 4 secs. find the speed of the particle

Answer 1

Answer:

Given:

Radius of circular track = 7 m

One revolution completed in 4 seconds.

To find:

Linear speed of object

Calculation:

Circumference of circle

= 2 × π × R

= 2 × (22/7) × 7

= 44 metres.

Now , for 1 revolution, the distance travelled = 44 metres

Linear speed = distance/time

=> v = 44/4

=> v = 11 m/s

So final answer is :

$\boxed{speed \: = 11 \: m {s}^{ - 1} }$

Answer 2

Answer:

${\boxed{\rm{Speed=11\:m{s}^{-1}}}}$

Explanation:

$\bf{Given}\begin{cases}\sf{Radius\:of\:circular\:path = 7\:m} \\\sf{Time\:taken=4\:s} \\\sf{Speed\:of\:particle=\:?}\end{cases}$

Formula used:-

${\boxed{\bold{Circumference\:of\:circle=2\pi r}}}$

$\rightarrow\tt Circumference = (2 \times 3.1416 \times 7)\:m \\\rightarrow\sf Circumference = 44\:m$

$\therefore\bold{Distance\:covered=44\:m}$

Formula used:-

${\boxed{\sf{Speed=\frac{Distance}{Time}}}}$

$\rightarrow\sf Speed =\frac{44\:m}{4\:s}$

$\rightarrow{\boxed{\sf {Speed = 11 \:m{s}^{-1}}}}$

$\therefore\bold{\underline{Speed\:of\:particle=11\:m{s}^{-1}}}$