Question

A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/2r^2
Its total energy is
(1) zero
(2) -3k/2a^2
(3) -k/4a^2
(4) k/2a^2​

Answer 1

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

⭐Actually Welcome to the Concept of the kinematics

❄So after solving we get as,