Question

A particle is moving in a circular path of radius a under the action of an attractive potential U = \rm{-\frac{k}{2r^2}}

Its
total energy will be:

(a)
$\rm{-\frac{3k}{2a^2}}$
(b)
$\rm{-\frac{k}{4a^2}}$
(c)
$\rm{\frac{k}{2a^2}}$
(d) Zero

Explanation needed ​

Answer 1

sorry I didn't understand your question