a particle is moving in a circular path of radius r. the magnitude of displacement of the particle after covering 1/4 of the circle is
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1
Answer:
Root2 r
Explanation:
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Given:
The radius of circular path = r
The distance covered = 1/4 of circle
To Find:
The magnitude of displacement of the particle.
Calculation:
- The displacement of particle = The distance between its start and end point.
- Since the particle has travelled 1/4 of the circle;
⇒ Its start and end point forms a right angled triangle with 2 sides equal to r and we have to find the hypotenuse 'd'.
- Applying Pythagoras theorem, we get:
d² = r² + r²
⇒ d² = 2r²
⇒ d = r√2
- Hence, the magnitude of displacement of the particle is r√2.
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