Physics, asked by blehblehbleh14, 10 months ago

a particle is moving in a circular path of radius r. the magnitude of displacement of the particle after covering 1/4 of the circle is​

Answers

Answered by siddhantgupt2004
1

Answer:

Root2 r

Explanation:

Answered by Jasleen0599
7

Given:

The radius of circular path = r

The distance covered = 1/4 of circle

To Find:

The magnitude of displacement of the particle.

Calculation:

- The displacement of particle = The distance between its start and end point.

- Since the particle has travelled 1/4 of the circle;

⇒ Its start and end point forms a right angled triangle with 2 sides equal to r and we have to find the hypotenuse 'd'.

- Applying Pythagoras theorem, we get:

d² = r² + r²

⇒ d² = 2r²

d = r√2

- Hence, the magnitude of displacement of the particle is r√2.

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