Question

a particle is moving in a circular path of radius r with uniform velocity v. the magnitude of change in velocity moving from P to Q is

Answer 1

Answer:

A particle is moving on a circular path of radius r with uniform speed V. The magnitude of change in velocity when the particle moves from P to Q is :- (∠PPOQ=40o)

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Answer 2

$ANSWER</p><p></p><p>Let the velocity at point P</p><p></p><p>v1=vi^</p><p></p><p></p><p>So the velocity at point Q will be </p><p></p><p>v2=vcos400i^−vsin400j^</p><p></p><p></p><p>  Change in velocity </p><p></p><p>Δv=v2−v1=(vcos400i^−vsin400j^)−vi^ </p><p></p><p></p><p> Magnitude of change of velocity </p><p></p><p>∣Δv∣=(vcos400−v)2+(−vsin400)2</p><p></p><p></p><p>On solving we get</p><p></p><p>∣Δv∣=2vsin200</p><p></p><p>$

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