A particle is moving in a circular path with constant kinetic energy K and time period T .The angular momentum of the particle about the centre of the path is
A-- KT/4π
B-- KT/2π
C-- KT/π
C-- 2KT/π
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0
Answer:
Centripetal acceleration, a
c
=k
2
rt
2
where, a
c
=
r
v
2
⇒
r
v
2
=k
2
rt
2
⇒v=krt ........(1)
Tangential acceleration, a
t
=
dt
dv
=kr.........(2)
Tangential force acting on the particle, F=ma
t
=mkr
Power delivered, P=
F
.
v
=Fvcosθ
∴ P=Fv=(mkr)×krt (∵θ=0
o
)
⟹P=mk
2
r
2
t
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