a particle is moving in a circular path with velocity varies with time as v- 1.5t^2+2t. if 2cm the radius of circular path. the angular acceleration at t-2 second will be?
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Dv/dt= 3t+2
and dv/dt == acceletation put t=2
acclrtion = 8 hence angular acclrtn = 8/2 =4
and dv/dt == acceletation put t=2
acclrtion = 8 hence angular acclrtn = 8/2 =4
abhaykumarsainik880:
Bt answer is 400rad/sec^2
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