Question

A particle is moving in a straight line such that its
displacement (X) is related to time (t) as
x = (3 - 4 + 5t?)m. The correct velocity-time
(v-t) graph will be

​

Answer 1

Answer:

option b

Explanation:

$v= \frac{dx}{dt} \\ = \frac{d}{dt} (5 {t}^{2} - 4t + 3) \\ = 10t - 4$

v= 10t-4 is similar to the straight line equation y=mx+c with slope=10 and y coordinate -4.

so,our v-t graph will be a straight line.

and the correct answer will be option b.

(here, the first graph is also a straight line,but it's y coordinate is positive,

and we know that it is -4.so the graph must start from -ve y axis)

hope it helps you... thank you...!!