Question

a particle is moving in a straight line under constant acceleration of 4m/ second square if its velocity at t=0 is 10 m/s the displacement of a particle in the 5th second of its motion is


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Answer 1

Answer:

100m

Explanation:

We are given

a=4m/s

and at t=0, velocity (u)=10m/s

Now, s=ut+1/2×at^2

here, t=5s

s=(10)(5)+1/2(4)(5)^2

s=50+2(5)^2

s=50+2(25)

s=50+50

s=100m

Thus displacement is 100m.

Hope it helps.

Answer 2

Answer:

28 meter

Explanation:

a=4m/sec^2

at t=0, u=10m/sec

displacement in 5th sec

Sn= u+1/2a(2t-1)

= 10+1/2*4(2*5-1)

= 10+2(10-1)

= 10+2*9

= 10+18

Sn = 28 meter

Hence displacement in 5th sec is 28 meter.